From 5965ae79a888ff1d7b757888f2b2510ea9570b7d Mon Sep 17 00:00:00 2001
From: Lakshya Thakur <lapstjup@gmail.com>
Date: Sat, 9 Jan 2021 17:00:00 +0530
Subject: [PATCH] Update currying function to use bind instead of wrapper pass

I think this change will help us to dodge concatenating new arguments with lexical ones and make the currying function much simpler.
---
 .../03-currying-partials/article.md           | 20 ++++++-------------
 1 file changed, 6 insertions(+), 14 deletions(-)

diff --git a/1-js/99-js-misc/03-currying-partials/article.md b/1-js/99-js-misc/03-currying-partials/article.md
index bb308847..2f91197f 100644
--- a/1-js/99-js-misc/03-currying-partials/article.md
+++ b/1-js/99-js-misc/03-currying-partials/article.md
@@ -121,11 +121,7 @@ function curry(func) {
   return function curried(...args) {
     if (args.length >= func.length) {
       return func.apply(this, args);
-    } else {
-      return function(...args2) {
-        return curried.apply(this, args.concat(args2));
-      }
-    }
+    } else return curried.bind(this, ...args);
   };
 
 }
@@ -154,26 +150,22 @@ The result of `curry(func)` call is the wrapper `curried` that looks like this:
 function curried(...args) {
   if (args.length >= func.length) { // (1)
     return func.apply(this, args);
-  } else {
-    return function pass(...args2) { // (2)
-      return curried.apply(this, args.concat(args2));
-    }
-  }
+  } else return curried.bind(this, ...args);
 };
 ```
 
 When we run it, there are two `if` execution branches:
 
 1. Call now: if passed `args` count is the same as the original function has in its definition (`func.length`) or longer, then just pass the call to it.
-2. Get a partial: otherwise, `func` is not called yet. Instead, another wrapper `pass` is returned, that will re-apply `curried` providing previous arguments together with the new ones. Then on a new call, again, we'll get either a new partial (if not enough arguments) or, finally, the result.
+2. Get a partial: otherwise, `func` is not called yet. Instead, a new bounded function using curried is returned, that takes the `...args` i.e. the current arguments as pre-specified. Then on a new call, again, we'll get either a new partial (if not enough arguments) or, finally, the result.
 
 For instance, let's see what happens in the case of `sum(a, b, c)`. Three arguments, so `sum.length = 3`.
 
 For the call `curried(1)(2)(3)`:
 
-1. The first call `curried(1)` remembers `1` in its Lexical Environment, and returns a wrapper `pass`.
-2. The wrapper `pass` is called with `(2)`: it takes previous args (`1`), concatenates them with what it got `(2)` and calls `curried(1, 2)` with them together. As the argument count is still less than 3, `curry` returns `pass`.
-3. The wrapper `pass` is called again with `(3)`,  for the next call `pass(3)` takes previous args (`1`, `2`) and adds `3` to them, making the call `curried(1, 2, 3)` -- there are `3` arguments at last, they are given to the original function.
+1. The first call `curried(1)` returns a new bounded `curried` with `1` as pre-specified argument.
+2. The bounded `curried` is called with `(2)`: it takes previous args (`1`) due to bind, and new leading argument `(2)` and calls `curried(2)`. As the argument count is still less than 3, `curry` returns new bounded `curried` with (`1`, `2`) as pre-specified arguments.
+3. The bounded `curried` is called again with `(3)`, for the next call `curried(3)` takes previous args (`1`, `2`) and new leading argument `3`, making the call `curried(3)` -- there are `3` arguments at last, they are given to the original function.
 
 If that's still not obvious, just trace the calls sequence in your mind or on paper.