From f4cb058d7f969b8f3b14e4de6b29a1aced0c9f90 Mon Sep 17 00:00:00 2001
From: wonderingabout <dota2orgoweiqibaduk@gmail.com>
Date: Sun, 29 Mar 2020 08:05:46 +0200
Subject: [PATCH] trick get a new copy of objects/arrays using the spread
 operator

---
 .../02-rest-parameters-spread/article.md      | 45 +++++++++++++++++++
 1 file changed, 45 insertions(+)

diff --git a/1-js/06-advanced-functions/02-rest-parameters-spread/article.md b/1-js/06-advanced-functions/02-rest-parameters-spread/article.md
index 74c85d4f..fad6dc5c 100644
--- a/1-js/06-advanced-functions/02-rest-parameters-spread/article.md
+++ b/1-js/06-advanced-functions/02-rest-parameters-spread/article.md
@@ -225,6 +225,51 @@ But there's a subtle difference between `Array.from(obj)` and `[...obj]`:
 So, for the task of turning something into an array, `Array.from` tends to be more universal.
 
 
+## Get a new copy of an object/array
+
+Remember when we talked about `Object.assign()` [in the past](https://javascript.info/symbol#symbols-are-skipped-by-for-in)?
+
+It is possible to do the same thing with the spread operator!
+
+```
+let arr = [1, 2, 3];
+let arrCopy = [...arr]; // spread the array into a list of parameters
+                        // then put the result into a new array
+
+// do the arrays have the same contents?
+alert(JSON.stringify(arr) === JSON.stringify(arrCopy)); // true
+
+// are the arrays equal?
+alert(arr === arrCopy); // false (not same reference)
+
+// modifying our initial array does not modify the copy:
+arr.push(4);
+alert(arr); // 1, 2, 3, 4
+alert(arrCopy); // 1, 2, 3
+```
+
+Note that it is possible to do the same thing to make a copy of an object:
+
+```
+let obj = { a: 1, b: 2, c: 3 };
+let objCopy = { ...obj }; // spread the object into a list of parameters
+                          // then return the result in a new object
+
+// do the objects have the same contents?
+alert(JSON.stringify(obj) === JSON.stringify(objCopy)); // true
+
+// are the objects equal?
+alert(obj === objCopy); // false (not same reference)
+
+// modifying our initial object does not modify the copy:
+obj.d = 4;
+alert(JSON.stringify(obj)); // {"a":1,"b":2,"c":3,"d":4}
+alert(JSON.stringify(objCopy)); // {"a":1,"b":2,"c":3}
+```
+
+This way of copying an object is much shorter than `let objCopy = Object.assign({}, obj);` or for an array `let arrCopy = Object.assign([], arr);` so we prefer to use it whenever we can.
+
+
 ## Summary
 
 When we see `"..."` in the code, it is either rest parameters or the spread syntax.