From c6620f6b9df4fcbf41bf3c4df0f4c390b9630f75 Mon Sep 17 00:00:00 2001 From: Alexey Pyltsyn Date: Thu, 13 Jun 2019 11:49:20 +0300 Subject: [PATCH] Fix typo --- .../05-output-single-linked-list-reverse/solution.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/1-js/06-advanced-functions/01-recursion/05-output-single-linked-list-reverse/solution.md b/1-js/06-advanced-functions/01-recursion/05-output-single-linked-list-reverse/solution.md index a9ba0baf..4357ff20 100644 --- a/1-js/06-advanced-functions/01-recursion/05-output-single-linked-list-reverse/solution.md +++ b/1-js/06-advanced-functions/01-recursion/05-output-single-linked-list-reverse/solution.md @@ -37,7 +37,7 @@ The loop variant is also a little bit more complicated then the direct output. There is no way to get the last value in our `list`. We also can't "go back". -So what we can do is to first go through the items in the direct order and rememeber them in an array, and then output what we remembered in the reverse order: +So what we can do is to first go through the items in the direct order and remember them in an array, and then output what we remembered in the reverse order: ```js run let list = {