Fix and add details to result array explanation
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1 changed files with 10 additions and 8 deletions
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@ -1,6 +1,6 @@
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A regexp for a number is: `pattern:-?\d+(\.\d+)?`. We created it in previous tasks.
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A regexp for a number is: `pattern:-?\d+(\.\d+)?`. We created it in previous tasks.
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An operator is `pattern:[-+*/]`. We put a dash `pattern:-` the first, because in the middle it would mean a character range, we don't need that.
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An operator is `pattern:[-+*/]`. We put the dash `pattern:-` first, because in the middle it would mean a character range, we don't need that.
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Note that a slash should be escaped inside a JavaScript regexp `pattern:/.../`.
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Note that a slash should be escaped inside a JavaScript regexp `pattern:/.../`.
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@ -21,15 +21,17 @@ alert( "1.2 + 12".match(reg) );
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The result includes:
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The result includes:
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- `result[0] == "1.2 + 12"` (full match)
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- `result[0] == "1.2 + 12"` (full match)
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- `result[1] == "1"` (first parentheses)
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- `result[1] == "1.2"` (first group `(-?\d+(\.\d+)?)` -- the first number, including the decimal part)
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- `result[2] == "2"` (second parentheses -- the decimal part `(\.\d+)?`)
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- `result[2] == ".2"` (second group`(\.\d+)?` -- the first decimal part)
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- `result[3] == "+"` (...)
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- `result[3] == "+"` (third group `([-+*\/])` -- the operator)
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- `result[4] == "12"` (...)
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- `result[4] == "12"` (forth group `(-?\d+(\.\d+)?)` -- the second number)
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- `result[5] == undefined` (the last decimal part is absent, so it's undefined)
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- `result[5] == undefined` (fifth group `(\.\d+)?` -- the last decimal part is absent, so it's undefined)
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We need only numbers and the operator. We don't need decimal parts.
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We only want the numbers and the operator, without the full match or the decimal parts.
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So let's remove extra groups from capturing by added `pattern:?:`, for instance: `pattern:(?:\.\d+)?`.
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The full match (the arrays first item) can be removed by shifting the array `pattern:result.shift()`.
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The decimal groups can be removed by making them into non-capturing groups, by adding `pattern:?:` to the beginning: `pattern:(?:\.\d+)?`.
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The final solution:
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The final solution:
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