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Ilya Kantor 2019-05-09 20:37:45 +03:00
parent b9714f12c8
commit 2035e46305
2 changed files with 5 additions and 5 deletions
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9-regular-expressions/04-regexp-escaping/article.md
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@ -61,7 +61,7 @@ let reg = new RegExp("\d\.\d");
alert( "Chapter 5.1".match(reg) ); // null
```
It worked with `pattern:/\d\.\d/`, but with `new RegExp("\d\.\d")` it doesn't, why?
The search worked with `pattern:/\d\.\d/`, but with `new RegExp("\d\.\d")` it doesn't work, why?
The reason is that backslashes are "consumed" by a string. Remember, regular strings have their own special characters like `\n`, and a backslash is used for escaping.
@ -77,7 +77,7 @@ The quotes "consume" backslashes and interpret them, for instance:
- `\u1234` -- becomes the Unicode character with such code,
- ...And when there's no special meaning: like `\d` or `\z`, then the backslash is simply removed.
So the call to `new RegExp` gets a string without backslashes. That's why it doesn't work!
So the call to `new RegExp` gets a string without backslashes. That's why the search doesn't work!
To fix it, we need to double backslashes, because quotes turn `\\` into `\`: