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reg->regexp

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This commit is contained in:
Ilya Kantor 2019-09-06 16:50:41 +03:00
parent 4232a53219
commit 32e20fc97c
35 changed files with 132 additions and 132 deletions
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12
9-regular-expressions/12-regexp-backreferences/article.md
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@ -17,10 +17,10 @@ We can put both kinds of quotes in the square brackets: `pattern:['"](.*?)['"]`,
```js run
let str = `He said: "She's the one!".`;
let reg = /['"](.*?)['"]/g;
let regexp = /['"](.*?)['"]/g;
// The result is not what we'd like to have
alert( str.match(reg) ); // "She'
alert( str.match(regexp) ); // "She'
```
As we can see, the pattern found an opening quote `match:"`, then the text is consumed till the other quote `match:'`, that closes the match.
@ -33,10 +33,10 @@ Here's the correct code:
let str = `He said: "She's the one!".`;
*!*
let reg = /(['"])(.*?)\1/g;
let regexp = /(['"])(.*?)\1/g;
*/!*
alert( str.match(reg) ); // "She's the one!"
alert( str.match(regexp) ); // "She's the one!"
```
Now it works! The regular expression engine finds the first quote `pattern:(['"])` and memorizes its content. That's the first capturing group.
@ -65,8 +65,8 @@ In the example below the group with quotes is named `pattern:?<quote>`, so the b
let str = `He said: "She's the one!".`;
*!*
let reg = /(?<quote>['"])(.*?)\k<quote>/g;
let regexp = /(?<quote>['"])(.*?)\k<quote>/g;
*/!*
alert( str.match(reg) ); // "She's the one!"
alert( str.match(regexp) ); // "She's the one!"
```