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Ahmed Bouhamra 2019-08-03 01:39:03 +00:00
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1-js/02-first-steps/14-function-basics/article.md
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@ -338,7 +338,17 @@ That doesn't work, because JavaScript assumes a semicolon after `return`. That'l
return*!*;*/!* return*!*;*/!*
(some + long + expression + or + whatever * f(a) + f(b)) (some + long + expression + or + whatever * f(a) + f(b))
``` ```
So, it effectively becomes an empty return. We should put the value on the same line instead. So, it effectively becomes an empty return.
If we wanted our expression to wrap across multiple lines, we would have to put the opening parenthesis in the same line as the `return` statement as follows:
```js
return (
some + long + expression
+ or +
whatever * f(a) + f(b)
)
```
And it will work just as we expect it to.
```` ````
## Naming a function [#function-naming] ## Naming a function [#function-naming]