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Fix a typo

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Chao Zhang 2020-03-10 20:17:35 -04:00 • committed by GitHub
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1-js/09-classes/02-class-inheritance/article.md
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@ -438,7 +438,7 @@ It works as intended, due to `[[HomeObject]]` mechanics. A method, such as `long
As we've known before, generally functions are "free", not bound to objects in JavaScript. So they can be copied between objects and called with another `this`.
The very existance of `[[HomeObject]]` violates that principle, because methods remember their objects. `[[HomeObject]]` can't be changed, so this bond is forever.
The very existence of `[[HomeObject]]` violates that principle, because methods remember their objects. `[[HomeObject]]` can't be changed, so this bond is forever.
The only place in the language where `[[HomeObject]]` is used -- is `super`. So, if a method does not use `super`, then we can still consider it free and copy between objects. But with `super` things may go wrong.