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closes #1591

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Ilya Kantor 2019-12-03 03:19:50 +03:00
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2-ui/1-document/07-modifying-document/12-sort-table/solution.md
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@ -2,22 +2,18 @@ The solution is short, yet may look a bit tricky, so here I provide it with exte
```js ```js
let sortedRows = Array.from(table.rows) // (1) let sortedRows = Array.from(table.tBodies[0].rows) // (1)
.slice(1) // (2) .sort((rowA, rowB) => rowA.cells[0].innerHTML > rowB.cells[0].innerHTML ? 1 : -1); // (2)
.sort((rowA, rowB) => rowA.cells[0].innerHTML > rowB.cells[0].innerHTML ? 1 : -1); // (3)
table.tBodies[0].append(...sortedRows); // (4) table.tBodies[0].append(...sortedRows); // (3)
``` ```
The step-by-step algorthm: The step-by-step algorthm:
1. Get all `<tr>`, like `table.querySelectorAll('tr')`, then make an array from them, cause we need array methods. 1. Get all `<tr>`, from `<tbody>`.
2. The first TR (`table.rows[0]`) is actually a table header, so we take the rest by `.slice(1)`. 2. Then sort them comparing by the content of the first `<td>` (the name field).
3. Then sort them comparing by the content of the first `<td>` (the name field). 3. Now insert nodes in the right order by `.append(...sortedRows)`.
4. Now insert nodes in the right order by `.append(...sortedRows)`.
Tables always have an implicit `<tbody>` element, so we must insert into it as `table.tBodes[0].append(...)`: a simple `table.append(...)` would fail.
Please note: we don't have to remove row elements, just "re-insert", they leave the old place automatically. Please note: we don't have to remove row elements, just "re-insert", they leave the old place automatically.
P.S. This solution assumes that the table doesn't have multple `<tbody>` (the common case). In case it does, we can modify the code accordingly: take rows only from the needed `<tbody>` in step `(1)` and insert them in that `<tbody>` step `(4)`. Also note: even if the table HTML doesn't have `<tbody>`, the DOM structure always has it. So we must insert elements as `table.tBodes[0].append(...)`: a simple `table.append(...)` would fail.