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\b instead of \  in word boundary 2 example
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YNataly 2017-10-18 20:57:37 +03:00 • committed by GitHub
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5-regular-expressions/03-regexp-character-classes/article.md
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@ -101,9 +101,9 @@ So it matches `pattern:\bHello\b` and `pattern:\bJava\b`, but not `pattern:\bHel
```js run
alert( "Hello, Java!".match(/\bHello\b/) ); // Hello
alert( "Hello, Java!".match(/\Java\b/) ); // Java
alert( "Hello, Java!".match(/\Hell\b/) ); // null
alert( "Hello, Java!".match(/\Java!\b/) ); // null
alert( "Hello, Java!".match(/\bJava\b/) ); // Java
alert( "Hello, Java!".match(/\bHell\b/) ); // null
alert( "Hello, Java!".match(/\bJava!\b/) ); // null
```
Once again let's note that `pattern:\b` makes the searching engine to test for the boundary, so that `pattern:Java\b` finds `match:Java` only when followed by a word boundary, but it does not add a letter to the result.