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"avoid" rather than "evade".
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paroche 2019-09-13 17:04:35 -06:00 • committed by GitHub
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1-js/08-prototypes/01-prototype-inheritance/4-hamster-proto/solution.md
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@ -44,7 +44,7 @@ alert( lazy.stomach ); // <nothing>
Now all works fine, because `this.stomach=` does not perform a lookup of `stomach`. The value is written directly into `this` object.
Also we can totally evade the problem by making sure that each hamster has their own stomach:
Also we can totally avoid the problem by making sure that each hamster has their own stomach:
```js run
let hamster = {