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# Escaping, special characters
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As we've seen, a backslash `"\"` is used to denote character classes. So it's a special character.
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There are other special characters as well, that have special meaning in a regexp. They are used to do more powerful searches.
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Here's a full list of them: `pattern:[ \ ^ $ . | ? * + ( )`.
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Don't try to remember it -- when we deal with each of them separately, you'll know it by heart automatically.
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## Escaping
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To use a special character as a regular one, prepend it with a backslash.
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That's also called "escaping a character".
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For instance, we need to find a dot `pattern:'.'`. In a regular expression a dot means "any character except a newline", so if we really mean "a dot", let's put a backslash before it: `pattern:\.`.
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```js run
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alert( "Chapter 5.1".match(/\d\.\d/) ); // 5.1
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```
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Parentheses are also special characters, so if we want them, we should use `pattern:\(`. The example below looks for a string `"g()"`:
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```js run
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alert( "function g()".match(/g\(\)/) ); // "g()"
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```
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If we're looking for a backslash `\`, then we should double it:
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```js run
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alert( "1\2".match(/\\/) ); // '\'
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```
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## A slash
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The slash symbol `'/'` is not a special character, but in JavaScript it is used to open and close the regexp: `pattern:/...pattern.../`, so we should escape it too.
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Here's what a search for a slash `'/'` looks like:
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```js run
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alert( "/".match(/\//) ); // '/'
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```
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From the other hand, the alternative `new RegExp` syntaxes does not require escaping it:
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```js run
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alert( "/".match(new RegExp("/")) ); // '/'
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```
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## new RegExp
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If we are creating a regular expression with `new RegExp`, then we need to do some more escaping.
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For instance, consider this:
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```js run
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let reg = new RegExp("\d\.\d");
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alert( "Chapter 5.1".match(reg) ); // null
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```
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It doesn't work, but why?
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The reason is string escaping rules. Look here:
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```js run
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alert("\d\.\d"); // d.d
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```
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Backslashes are used for escaping inside a string and string-specific special characters like `\n`. The quotes "consume" and interpret them, for instance:
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- `\n` -- becomes a newline character,
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- `\u1234` -- becomes the Unicode character with such code,
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- ...And when there's no special meaning: like `\d` or `\z`, then the backslash is simply removed.
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So the call to `new RegExp` gets a string without backslashes.
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To fix it, we need to double backslashes, because quotes turn `\\` into `\`:
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```js run
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*!*
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let regStr = "\\d\\.\\d";
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*/!*
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alert(regStr); // \d\.\d (correct now)
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let reg = new RegExp(regStr);
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alert( "Chapter 5.1".match(reg) ); // 5.1
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```
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