closure
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5b195795da
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39 changed files with 365 additions and 461 deletions
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function makeArmy() {
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let shooters = [];
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for(let i = 0; i < 10; i++) {
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let shooter = function() { // shooter function
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alert( i ); // should show its number
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};
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shooters.push(shooter);
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}
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return shooters;
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}
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function makeArmy() {
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let shooters = [];
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let i = 0;
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while (i < 10) {
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let shooter = function() { // shooter function
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alert( i ); // should show its number
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};
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shooters.push(shooter);
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i++;
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}
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return shooters;
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}
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/*
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let army = makeArmy();
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army[0](); // the shooter number 0 shows 10
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army[5](); // and number 5 also outputs 10...
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// ... all shooters show 10 instead of their 0, 1, 2, 3...
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*/
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describe("army", function() {
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let army;
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before(function() {
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army = makeArmy();
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window.alert = sinon.stub(window, "alert");
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});
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it("army[0] shows 0", function() {
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army[0]();
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assert(alert.calledWith(0));
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});
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it("army[5] shows 5", function() {
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army[5]();
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assert(alert.calledWith(5));
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});
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after(function() {
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window.alert.restore();
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});
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});
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120
1-js/06-advanced-functions/03-closure/10-make-army/solution.md
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120
1-js/06-advanced-functions/03-closure/10-make-army/solution.md
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Let's examine what's done inside `makeArmy`, and the solution will become obvious.
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1. It creates an empty array `shooters`:
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```js
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let shooters = [];
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```
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2. Fills it in the loop via `shooters.push(function...)`.
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Every element is a function, so the resulting array looks like this:
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```js no-beautify
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shooters = [
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); },
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function () { alert(i); }
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];
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```
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3. The array is returned from the function.
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Then, later, the call to `army[5]()` will get the element `army[5]` from the array (it will be a function) and call it.
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Now why all such functions show the same?
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That's because there's no local variable `i` inside `shooter` functions. When such a function is called, it takes `i` from its outer lexical environment.
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What will be the value of `i`?
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If we look at the source:
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```js
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function makeArmy() {
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...
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let i = 0;
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while (i < 10) {
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let shooter = function() { // shooter function
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alert( i ); // should show its number
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};
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...
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}
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...
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}
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```
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...We can see that it lives in the lexical environment associated with the current `makeArmy()` run. But when `army[5]()` is called, `makeArmy` has already finished its job, and `i` has the last value: `10` (the end of `while`).
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As a result, all `shooter` functions get from the outer lexical envrironment the same, last value `i=10`.
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We can fix it by moving the variable definition into the loop:
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```js run demo
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function makeArmy() {
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let shooters = [];
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*!*
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for(let i = 0; i < 10; i++) {
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*/!*
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let shooter = function() { // shooter function
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alert( i ); // should show its number
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};
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shooters.push(shooter);
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}
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return shooters;
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}
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let army = makeArmy();
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army[0](); // 0
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army[5](); // 5
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```
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Now it works correctly, because every time the code block in `for (let i=0...) {...}` is executed, a new Lexical Environment is created for it, with the corresponding variable `i`.
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So, the value of `i` now lives a little bit closer. Not in `makeArmy()` Lexical Environment, but in the Lexical Environment that corresponds the current loop iteration. That's why now it works.
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Here we rewrote `while` into `for`.
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Another trick could be possible, let's see it for better understanding of the subject:
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```js run
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function makeArmy() {
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let shooters = [];
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let i = 0;
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while (i < 10) {
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*!*
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let j = i;
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*/!*
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let shooter = function() { // shooter function
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alert( *!*j*/!* ); // should show its number
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};
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shooters.push(shooter);
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i++;
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}
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return shooters;
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}
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let army = makeArmy();
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army[0](); // 0
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army[5](); // 5
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```
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The `while` loop, just like `for`, makes a new Lexical Environment for each run. So here we make sure that it gets the right value for a `shooter`.
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We copy `let j = i`. This makes a loop body local `j` and copies the value of `i` to it. Primitives are copied "by value", so we actually get a complete independent copy of `i`, belonging to the current loop iteration.
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35
1-js/06-advanced-functions/03-closure/10-make-army/task.md
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35
1-js/06-advanced-functions/03-closure/10-make-army/task.md
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importance: 5
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---
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# Army of functions
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The following code creates an array of `shooters`.
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Every function is meant to output its number. But something is wrong...
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```js run
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function makeArmy() {
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let shooters = [];
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let i = 0;
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while (i < 10) {
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let shooter = function() { // shooter function
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alert( i ); // should show its number
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};
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shooters.push(shooter);
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i++;
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}
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return shooters;
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}
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let army = makeArmy();
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army[0](); // the shooter number 0 shows 10
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army[5](); // and number 5 also outputs 10...
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// ... all shooters show 10 instead of their 0, 1, 2, 3...
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```
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Why do all of the shooters show the same value? Fix the code so that they work as intended.
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