This commit is contained in:
Ilya Kantor 2017-03-21 17:14:05 +03:00
parent ab9ab64bd5
commit 97c8f22bbb
289 changed files with 195 additions and 172 deletions

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Any `setTimeout` will run only after the current code has finished.
The `i` will be the last one: `100000000`.
```js run
let i = 0;
setTimeout(() => alert(i), 100); // 100000000
// assume that the time to execute this function is >100ms
for(let j = 0; j < 100000000; j++) {
i++;
}
```

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importance: 5
---
# What will setTimeout show?
In the code below there's a `setTimeout` call scheduled, then a heavy calculation is run, that takes more than 100ms to finish.
When the scheduled function will run?
1. After the loop.
2. Before the loop.
3. In the beginning of the loop.
What `alert` is going to show?
```js
let i = 0;
setTimeout(() => alert(i), 100); // ?
// assume that the time to execute this function is >100ms
for(let j = 0; j < 100000000; j++) {
i++;
}
```