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The solution: `pattern:/"(\\.|[^"\\])*"/g`.
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Step by step:
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- First we look for an opening quote `pattern:"`
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- Then if we have a backslash `pattern:\\` (we technically have to double it in the pattern, because it is a special character, so that's a single backslash in fact), then any character is fine after it (a dot).
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- Otherwise we take any character except a quote (that would mean the end of the string) and a backslash (to prevent lonely backslashes, the backslash is only used with some other symbol after it): `pattern:[^"\\]`
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- ...And so on till the closing quote.
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In action:
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```js run
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let reg = /"(\\.|[^"\\])*"/g;
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let str = ' .. "test me" .. "Say \\"Hello\\"!" .. "\\\\ \\"" .. ';
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alert( str.match(reg) ); // "test me","Say \"Hello\"!","\\ \""
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```
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# Find quoted strings
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Create a regexp to find strings in double quotes `subject:"..."`.
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The important part is that strings should support escaping, in the same way as JavaScript strings do. For instance, quotes can be inserted as `subject:\"` a newline as `subject:\n`, and the slash itself as `subject:\\`.
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```js
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let str = "Just like \"here\".";
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```
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For us it's important that an escaped quote `subject:\"` does not end a string.
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So we should look from one quote to the other ignoring escaped quotes on the way.
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That's the essential part of the task, otherwise it would be trivial.
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Examples of strings to match:
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```js
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.. *!*"test me"*/!* ..
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.. *!*"Say \"Hello\"!"*/!* ... (escaped quotes inside)
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.. *!*"\\"*/!* .. (double slash inside)
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.. *!*"\\ \""*/!* .. (double slash and an escaped quote inside)
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```
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In JavaScript we need to double the slashes to pass them right into the string, like this:
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```js run
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let str = ' .. "test me" .. "Say \\"Hello\\"!" .. "\\\\ \\"" .. ';
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// the in-memory string
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alert(str); // .. "test me" .. "Say \"Hello\"!" .. "\\ \"" ..
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```
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