up

1-js/2-first-steps/8-operators/3-primitive-conversions-questions/solution.md

@@ -0,0 +1,26 @@
+
+
+```js
+//+ no-beautify
+"" + 1 + 0 = "10" // (1)
+"" - 1 + 0 = -1 // (2)
+true + false = 1
+6 / "3" = 2 
+"2" * "3" = 6
+4 + 5 + "px" = "9px"
+"$" + 4 + 5
 = "$45"
+"4" - 2
 = 2 
+"4px" - 2
 = NaN
+7 / 0
 = Infinity 
+" -9\n" + 5 = " -9\n5"
+" -9\n" - 5 = -14
+null + 1 = 1 // (3)
+undefined + 1 = NaN // (4)
+```
+
+<ol>
+<li>The plus `"+"` operator in this case first converts `1` to a string: `"" + 1 = "1"`, and then adds `0`.</li>
+<li>The minus `"-"` operator only works with numbers, it converts an empty string `""` to zero immediately.</li>
+<li>`null` becomes `0` after the numeric conversion.</li>
+<li>`undefined` becomes `NaN` after the numeric conversion.</li>
+</ol>

1-js/2-first-steps/8-operators/3-primitive-conversions-questions/task.md

@@ -0,0 +1,26 @@
+# Type conversions
+
+[importance 5]
+
+Let's recap type conversions in the context of operators.
+
+What will be the result for expressions?
+
+```js
+//+ no-beautify
+"" + 1 + 0 
+"" - 1 + 0
+true + false
+6 / "3"
+"2" * "3"
+4 + 5 + "px"
+"$" + 4 + 5
 
+"4" - 2
 
+"4px" - 2

+7 / 0
 
+"  -9\n" + 5 
+"  -9\n" - 5
+null + 1
+undefined + 1
+```
+