minor fixes

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Ilya Kantor 2020-10-17 21:50:55 +03:00
parent 10d1b1f25f
commit d6e88647b4

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@ -9,36 +9,64 @@ The optional chaining `?.` is a safe way to access nested object properties, eve
If you've just started to read the tutorial and learn JavaScript, maybe the problem hasn't touched you yet, but it's quite common.
As an example, let's consider objects for user data. Most of our users have addresses in `user.address` property, with the street `user.address.street`, but some did not provide them.
As an example, consider objects for user data. Most of our users have addresses in `user.address` property, with the street `user.address.street`, but some did not provide them.
In such case, when we attempt to get `user.address.street`, we'll get an error:
In such case, when we attempt to get `user.address.street`, we may get an error:
```js run
let user = {}; // the user without "address" property
let user = {}; // a user without "address" property
alert(user.address.street); // Error!
```
That's the expected result, JavaScript works like this, but many practical cases we'd prefer to get `undefined` instead of an error (meaning "no street").
That's the expected result, JavaScript works like this. As `user.address` is `undefined`, the attempt to get `user.address.street` fails with an error. Although, in many practical cases we'd prefer to get `undefined` instead of an error here (meaning "no street").
...And another example. In the web development, we may need to get an information about an element on the page, that sometimes doesn't exist:
...And another example. In the web development, we may need the information about an element on the page. The element is returned by `document.querySelector('.elem')`, and the catch is again - that it sometimes doesn't exist:
```js run
// Error if the result of querySelector(...) is null
let html = document.querySelector('.my-element').innerHTML;
// the result of the call document.querySelector('.elem') may be an object or null
let html = document.querySelector('.elem').innerHTML; // error if it's null
```
Before `?.` appeared in the language, the `&&` operator was used to work around that.
Once again, we may want to avoid the error in such case.
For example:
How can we do this?
The obvious solution would be to check the value using `if` or the conditional operator `?`, before accessing it, like this:
```js
let user = {};
alert(user.address ? user.address.street : undefined);
```
...But that's quite inelegant. As you can see, the `user.address` is duplicated in the code. For more deeply nested properties, that becomes a problem.
E.g. let's try getting `user.address.street.name`.
We need to check both `user.address` and `user.address.street`:
```js
let user = {}; // user has no address
alert(user.address ? user.address.street ? user.address.street.name : null : null);
```
That looks awful.
Before the optional chaining `?.` was added to the language, people used the `&&` operator for such cases:
```js run
let user = {}; // user has no address
alert( user && user.address && user.address.street ); // undefined (no error)
alert( user.address && user.address.street && user.address.street.name ); // undefined (no error)
```
AND'ing the whole path to the property ensures that all components exist (if not, the evaluation stops), but is cumbersome to write.
AND'ing the whole path to the property ensures that all components exist (if not, the evaluation stops), but also isn't ideal.
As you can see, the property names are still duplicated in the code. E.g. in the code above, `user.address` appears three times.
And now, finally, the optional chaining comes to the rescue!
## Optional chaining
@ -46,7 +74,7 @@ The optional chaining `?.` stops the evaluation and returns `undefined` if the p
**Further in this article, for brevity, we'll be saying that something "exists" if it's not `null` and not `undefined`.**
Here's the safe way to access `user.address.street`:
Here's the safe way to access `user.address.street` using `?.`:
```js run
let user = {}; // user has no address
@ -54,6 +82,8 @@ let user = {}; // user has no address
alert( user?.address?.street ); // undefined (no error)
```
The code is short and clean, there's no duplication at all.
Reading the address with `user?.address` works even if `user` object doesn't exist:
```js run
@ -65,14 +95,14 @@ alert( user?.address.street ); // undefined
Please note: the `?.` syntax makes optional the value before it, but not any further.
In the example above, `user?.` allows only `user` to be `null/undefined`.
In the example above, `user?.address.street` allows only `user` to be `null/undefined`.
On the other hand, if `user` does exist, then it must have `user.address` property, otherwise `user?.address.street` gives an error at the second dot.
```warn header="Don't overuse the optional chaining"
We should use `?.` only where it's ok that something doesn't exist.
For example, if according to our coding logic `user` object must be there, but `address` is optional, then `user.address?.street` would be better.
For example, if according to our coding logic `user` object must exist, but `address` is optional, then we should write `user.address?.street`, but not `user?.address?.street`.
So, if `user` happens to be undefined due to a mistake, we'll see a programming error about it and fix it. Otherwise, coding errors can be silenced where not appropriate, and become more difficult to debug.
```
@ -84,7 +114,7 @@ If there's no variable `user` at all, then `user?.anything` triggers an error:
// ReferenceError: user is not defined
user?.address;
```
There must be a declaration (e.g. `let/const/var user`). The optional chaining works only for declared variables.
The variable must be declared (e.g. `let/const/var user` or as a function parameter). The optional chaining works only for declared variables.
````
## Short-circuiting