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Fix Typo in logical operators

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true || alert("printed")
false || alert("not printed") 

This is confusing to a student as the first won't be printed, but the second will print "not printed". I've reversed it to this so it makes much more sense to a learner:

true || alert("not printed")
false || alert("printed")
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Moudi Kawi 2020-05-08 16:56:08 +01:00 • committed by GitHub
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1-js/02-first-steps/11-logical-operators/article.md
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@ -128,8 +128,8 @@ This leads to some interesting usage compared to a "pure, classical, boolean-onl
In the example below, the first message is printed, while the second is not: In the example below, the first message is printed, while the second is not:
```js run no-beautify ```js run no-beautify
*!*true*/!* || alert("printed"); *!*true*/!* || alert("not printed");
*!*false*/!* || alert("not printed"); *!*false*/!* || alert("printed");
``` ```
In the first line, the OR `||` operator stops the evaluation immediately upon seeing `true`, so the `alert` isn't run. In the first line, the OR `||` operator stops the evaluation immediately upon seeing `true`, so the `alert` isn't run.