f20fb43f70
I used the solution and examples already in the article. I chose to make the test cases use Array.reduce() to compute the sum, instead of hard-coding the answer myself. Not sure how good of practice that is.
57 lines
1.3 KiB
JavaScript
57 lines
1.3 KiB
JavaScript
/*
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* Instead of hard-coding a bunch of separate test cases and their solutions,
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* this code takes several argument lists, and compares the chain call answer
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* you made for "sum()" to a more traditional way of adding the contents of an
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* array.
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*/
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describe("sum", function(){
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let testArgumentLists = [
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[1, 2],
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[5, -1, 2],
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[6, -1, -2, -3],
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[0, 1, 2, 3, 4, 5],
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];
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for (let argumentList of testArgumentLists){
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it(makeTestCaseName(argumentList), function(){
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assert.equal(traditionalSum(argumentList), chainCallSum(argumentList));
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});
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}
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});
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function traditionalSum(arr){
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return arr.reduce(
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function(accumulator, item){
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return accumulator + item;
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}, 0);
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}
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function makeTestCaseName(arr){
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return `sum${makeChainCallString(arr)} == ${traditionalSum(arr)}`;
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}
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/* Takes the elements of an array, and puts them in a string where each element
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* is enclosed in parentheses. Example:
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*
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* (["a", "b", "c"]) => "(a)(b)(c)"
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*
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* Useful for making pretty test case names.
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*/
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function makeChainCallString(arr){
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return arr.reduce(
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function(accumulator, item){
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return `${accumulator}(${item})`;
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}, "");
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}
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function chainCallSum(arr){
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return arr.reduce(
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function(accumulator, item){
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return accumulator(item);
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}, sum);
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}
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