jeena/en.javascript.info
1
0
Fork 0
Code Issues Pull requests Projects Packages Wiki Activity Actions

Fix typo

Browse source
This commit is contained in:
Alexey Pyltsyn 2019-06-13 11:49:20 +03:00 • committed by GitHub
parent 852b9bf581
commit c6620f6b9d
No known key found for this signature in database
GPG key ID: 4AEE18F83AFDEB23
1 changed files with 1 additions and 1 deletions
Download patch file Download diff file Expand all files Collapse all files

2
1-js/06-advanced-functions/01-recursion/05-output-single-linked-list-reverse/solution.md
View file

@ -37,7 +37,7 @@ The loop variant is also a little bit more complicated then the direct output.
There is no way to get the last value in our `list`. We also can't "go back". There is no way to get the last value in our `list`. We also can't "go back".
So what we can do is to first go through the items in the direct order and rememeber them in an array, and then output what we remembered in the reverse order: So what we can do is to first go through the items in the direct order and remember them in an array, and then output what we remembered in the reverse order:
```js run ```js run
let list = { let list = {