en.javascript.info/9-regular-expressions/11-regexp-alternation/03-match-quoted-string/solution.md

The solution: pattern:/"(\\.|[^"\\])*"/g.

Step by step:

• First we look for an opening quote pattern:"
• Then if we have a backslash pattern:\\ (we technically have to double it in the pattern, because it is a special character, so that's a single backslash in fact), then any character is fine after it (a dot).
• Otherwise we take any character except a quote (that would mean the end of the string) and a backslash (to prevent lonely backslashes, the backslash is only used with some other symbol after it): pattern:[^"\\]
• ...And so on till the closing quote.

In action:

let reg = /"(\\.|[^"\\])*"/g;
let str = ' .. "test me" .. "Say \\"Hello\\"!" .. "\\\\ \\"" .. ';

alert( str.match(reg) ); // "test me","Say \"Hello\"!","\\ \""